Hello friends,
Welcome
you all in the C++ 11 Part2. In the Part1 we have discussed about auto and
decltype.
In this part we will learn about nullptr and
enum classes.
Let’s start with nullptr.
nullptr :-
nullptr
has been introduced in C++ 11. nullptr denotes the null pointer literal.
nullptr
is a of type nullptr_t, which is implicitly convertible and comparable to any
pointer type and
any pointer to member type.
Let's see this :-
void
fun1(char *i);
void
fun1(int j);
fun1(
NULL ); // which function gets
called ?
It
looks like the first function will be called.
The
trouble is value of NULL is integer 0, so the second fun1(int j) will be
called.
With
the help of nullptr we can solve this very easily.
fun1
( nullptr );
Now
the first function fun1(char *i) will be called. nullptr is used to represent
NULL pointers,
and
cannot be converted to an integer.
enum classes:-
We
have all used enums. Can you tell me is it type safe?
enums
in C++03 are not type safe. They are treated like as integer constant even if the
enumeration types
are distinct.
Let
see the example:-
#include < iostream> using namespace std; int main() { enum Song { track1, track2 }; enum Video { video1, video2 }; Song s = track1; Video v = video1; if (s == v) // The compiler will compare a and b as integers cout << "s and v are equal, no type safe" << endl; // and find they are equal! else cout << "s and v are not equal, type safe" << endl; return 0; }
C++11 has introduced enum class, which makes enums type safe and strongly scoped.
Lets take the same example with use of enum class.
Lets take the same example with use of enum class.
#include < iostream> using namespace std; int main() { enum class Song { track1, track2 }; enum class Video { video1, video2 }; Song s = Song::track1; // track1 is not accessible, we have to use :: operator Video v = Video::video1; // track1 is not accessible, we have to use :: operator if (s == v) // compile error here, as the compiler doesn't know how to compare different types Song and Video cout << "s and v are equal, no type safe" << endl; else cout << "s and v are not equal, type safe" << endl; return 0; }
enum class makes the enums strongly scoped. If you want to access it you have to use :: operator.
enum class makes the enums type safe. So C++ will look for an explicilty defined comparison function to compare Song and Video. Because we have not defined an operator==(Song, Video) function the compiler won't understand how to compare s and v. That is why it is giving compiler error.
enum class makes the enums type safe. So C++ will look for an explicilty defined comparison function to compare Song and Video. Because we have not defined an operator==(Song, Video) function the compiler won't understand how to compare s and v. That is why it is giving compiler error.
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